7x^2+168=77x

Solution for 7x^2+168=77x equation:

7x^2+168=77x

We move all terms to the left:

7x^2+168-(77x)=0

a = 7; b = -77; c = +168;
Δ = b2-4ac
Δ = -772-4·7·168
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-77)-35}{2*7}=\frac{42}{14}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-77)+35}{2*7}=\frac{112}{14}
=8
$